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>_>

Here, let's try another one.

 

If A=B, C is equal to D only when B + C = F, G is only equal to A when both D and C are negative, H = A on Thursday, C = F when the sandwich has pickles on it, A + F - a kidney stone = G when you sing a song, the pipe fills with joy and all say be hey dal LA, A doesn't actually equal B because that was a trick, brownies are a think mist that falls from the stars,  D doesn't actually exist, hidden in the bowels of cheese are tiny hats, D * 0 = 50, don't doddle on the space man, A = B if you believe in the power of love, H is actually just the letter H it's not even a variable, then what does Q equal on the third month of chamber pot?

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If A=B, C is equal to D only when B + C = F, G is only equal to A when both D and C are negative, H = A on Thursday, C = F when the sandwich has pickles on it, A + F - a kidney stone = G when you sing a song, the pipe fills with joy and all say be hey dal LA, A doesn't actually equal B because that was a trick, brownies are a think mist that falls from the stars,  D doesn't actually exist, hidden in the bowels of cheese are tiny hats, D * 0 = 50, don't doddle on the space man, A = B if you believe in the power of love, H is actually just the letter H it's not even a variable, then what does Q equal on the third month of chamber pot?

A=B

C=D : B+C=F

G=A : D<0, C<0

H=A : Thursday

C=F : Pickles (which means if Pickles, then B+C=F only if B=0, so C=D only if B=0)

A+F-K=G : Singing (Let K be a kidney store) (if D<0, C<0 and singing, then A=G so F-K=0, hence F=K)

A≠B (apparently earlier statement A=B revealed to be a typo, so no inconsistency)

∄D

D*0=50 (Verifies previous statement, no D exists such that D*0=50)

A=B : Love (If love, then A=B which contradicts previous line A≠B, hence there is no love)

H is not a variable (This only makes sense if 'H=A : Thursday' is treated as just a string of characters and not an equation)

 

No mention was made of the chamber pot, so it's effect on Q is unknown. In all of that, absolutely no restrictions were placed on the value of Q, so Q can still be anything. It is basically undefined.

  • Brohoof 2
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A=B

C=D : B+C=F

G=A : D<0, C<0

H=A : Thursday

C=F : Pickles (which means if Pickles, then B+C=F only if B=0, so C=D only if B=0)

A+F-K=G : Singing (Let K be a kidney store) (if D<0, C<0 and singing, then A=G so F-K=0, hence F=K)

A≠B (apparently earlier statement A=B revealed to be a typo, so no inconsistency)

∄D

D*0=50 (Verifies previous statement, no D exists such that D*0=50)

A=B : Love (If love, then A=B which contradicts previous line A≠B, hence there is no love)

H is not a variable (This only makes sense if 'H=A : Thursday' is treated as just a string of characters and not an equation)

 

No mention was made of the chamber pot, so it's effect on Q is unknown. In all of that, absolutely no restrictions were placed on the value of Q, so Q can still be anything. It is basically undefined.

How do you always find logic in my nonsensical gibberish?  :twi:

  • Brohoof 1
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It's funny how you concluded there was no such thing as love.  ^_^

That just followed from all the statements you presented! Love can't exist, because if it did, A would both equal B and not equal B. It's basically a proof by contradiction; were love to exist it leads to an inconsistency, so love can't exist.

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You are no match for the Empire!

*Heavy Breathing*

Victory to the Zurg!

Ha ha ha, how amusing! Do you truly think you can defeat me?

 

That just followed from all the statements you presented! Love can't exist, because if it did, A would both equal B and not equal B. It's basically a proof by contradiction; were love to exist it leads to an inconsistency, so love can't exist.

Okay, sure.  :twi:

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@,

 

Interesting Offer!,

 

Very well creature ,

*Heavy breathing*

if you take him down, you will receive the highest military rank in my Empire!

Edited by Emperor Zurg
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