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7 hours ago, mini said:

Introduction and setting are portrayed much better. I feel like I understand the character's world more. I like how the character's thoughts are spontaneously disrupted by "Stop," followed by a return to business as usual. This sense of duty foreshadows the conclusion. However, I'd like to change some parts if you don't mind.

 

This version is markedly better. I'm not sure why your teacher is refusing to give you proper feedback. sounds like a shit teacher tbh

Wow I actually can’t thank you enough for your help!:pinkie:  you have a real literary talent and I’m so grateful you’ve shared it with me:wub:

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Okay, this is probably a long shot but I'm desperate for any help.

So does anyone here use LibreOffice Calc for spreadsheets? I have a spreadsheet project due on Monday and I can't figure out how to resize the spreadsheet cells and columns properly. I tried googling how to but nothing I read was much of a help. :yeahno: Either that or I'm just too dumb lol

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2 minutes ago, Lucky Bat said:

Okay, this is probably a long shot but I'm desperate for any help.

So does anyone here use LibreOffice Calc for spreadsheets? I have a spreadsheet project due on Monday and I can't figure out how to resize the spreadsheet cells and columns properly. I tried googling how to but nothing I read was much of a help. :yeahno: Either that or I'm just too dumb lol

Can you just click and drag the lines like in Excel?

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Just now, Misty Breeze said:

Can you just click and drag the lines like in Excel?

What lines though? Cause I kept reading something about click and drag the borders and I'm like WHAT BORDERS :dry:

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Just now, Lucky Bat said:

What lines though? Cause I kept reading something about click and drag the borders and I'm like WHAT BORDERS :dry:

Like the line around each cell. 

Or try at the top and on the side where the row an column labels are like A, B, C, etc and 1, 2, 3, etc click and drag the line between those.

At least that's how Excel works.:adorkable:

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5 minutes ago, Misty Breeze said:

Like the line around each cell. 

Or try at the top and on the side where the row an column labels are like A, B, C, etc and 1, 2, 3, etc click and drag the line between those.

At least that's how Excel works.:adorkable:

I don't think that's how Libreoffice works. Either I'm just not seeing it or....it's an Excel thing 

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2 minutes ago, Lucky Bat said:

I don't think that's how Libreoffice works. Either I'm just not seeing it or....it's an Excel thing 

Just checked on a copy of libreoffice - if you move the cursor to the line between (say) A and B on the top bar, it turns into a double headed arrow like <--> ... if at that point you click and drag, it resizes the column to the left (A). same thing between the numbers

 

lr.png.1cb364638287eee5a4e85d9c95d91585.png                   ud.png.b75de6f65b4049d499b89b6f8c9b44cc.png

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11 minutes ago, CypherHoof said:

Just checked on a copy of libreoffice - if you move the cursor to the line between (say) A and B on the top bar, it turns into a double headed arrow like <--> ... if at that point you click and drag, it resizes the column to the left (A). same thing between the numbers

 

lr.png.1cb364638287eee5a4e85d9c95d91585.png                   ud.png.b75de6f65b4049d499b89b6f8c9b44cc.png

Oh my gosh thank you! That’s exactly what I was looking for! You’re a lifesaver :ButtercupLaugh:

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5 minutes ago, Lucky Bat said:

Oh my gosh thank you! That’s exactly what I was looking for! You’re a lifesaver :ButtercupLaugh:

NP, happy I could help :)

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Oh look who's back in here again. :sealed: 

I have a research paper due in a couple days. It's on potential planets (other than Earth of course :derp:) that could support life. Does anyone know of any good online sources where I could get some legitimate research info on this topic? I did find a couple things on the National Geographic website but I need more sources. I'm just curious if any of you know of any. Thanks! 

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12 minutes ago, Lucky Bells said:

Oh look who's back in here again. :sealed: 

I have a research paper due in a couple days. It's on potential planets (other than Earth of course :derp:) that could support life. Does anyone know of any good online sources where I could get some legitimate research info on this topic? I did find a couple things on the National Geographic website but I need more sources. I'm just curious if any of you know of any. Thanks! 

Have you tried the NASA official website? Sometimes they post articles for the general public regarding that kind of stuff.

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59 minutes ago, Jesse Terrence said:

Have you tried the NASA official website? Sometimes they post articles for the general public regarding that kind of stuff.

Ooh, Didn’t think of that. I’ll check it out, thanks! :grin:

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I'm pretty good in biology, zoology, and environmental science. I could help tutor if needed! Though the latter two are rather unconventional and I know not every school teaches those subjects I figured I could offer anyways. I'm currently at a senior level of high school so all the science I know doesn't reach into college level yet.

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I could use a hand with my Engineering homework:

5. Compute the magnitude of the following complex numbers:

a. 2 + j5

b. e jπ

c. 3ejπ/2

d. j 5/8

6. Simplify to a + jb form:

a. (2+j)/(1+j2) + (1+j)

b. e jπ/2 + j

c. (4+j3)/(1-j)

d. e jπ + (1+j)/(1-j)

While I understand all this in concept, my stumbling block is simplifying to fractional form in Radians. Need some pointers/cheat sheets about that.

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(edited)

It's been a while since I needed this, but let's try.

Disclaimer: I may have made some mistakes, missed a sign or something. If you give my answer to your teacher without verifying I am not responsible for a bad grade.

The magnitude of a complex number of the form (a+bj) can be calculated with Sqrt(a^2+b^2).

4 hours ago, Mirage said:

a. 2 + j5

b. e jπ

c. 3ejπ/2

d. j 5/8

a. Sqrt(2^2 + 5^2) = Sqrt(29)
b. Now this I can interpret two ways, either it is e*j*pi, in which case the magnitude is e*pi or, e^(j*pi), in which case the magnitude is 1. But I'm guessing that this and the other numbers with e in them are polar notation, just that the superscript formatting is lost here.
c. 3e^(j*pi/2) , the magnitude of this is 3. In polar notation, the magnitude is the number that e is multiplied by (in b it was 1) and the angle is what j is multiplied by.
d. OK, I have two ways to read this one as well, it's either j*5/8, in which case the magnitude is 5/8 or j^(5/8). This you can calculate like this: 
image.png.922eec95c4981a7f7ea984df98815f2e.png, in which case the magnitude is 1.

4 hours ago, Mirage said:

While I understand all this in concept, my stumbling block is simplifying to fractional form in Radians. Need some pointers/cheat sheets about that

The idea is this: You need to find the magnitude and the angle. You can find the magnitude by Sqrt(a^2+b^2) and the angle usually by arctan(b/a). However, this fails is a is zero. This is where you have to know three special cases:
0 + x*j, the angle is pi/2
0 - x^j, the angle is -pi/2 or 3pi/4 (they are equivalent)
0 + 0*j, the angle is undefined
all the other cases should work with arctan(b/a).

4 hours ago, Mirage said:

6. Simplify to a + jb form:

a. (2+j)/(1+j2) + (1+j)

1+j2 is either 1+j^2 or 1+j*2. If it's the first one, then 1+j^2 = 1-1 = 0 and you get division by zero, so let's assume it's the second one.
Let's convert 2+j and 1+j*2 to polar notation:
2+j. Magnitude = Sqrt(2^2+1^2)=Sqrt(5). Angle = arctan(1/2) (it does not evaluate to something pretty)
1+j2. Magnitude = Sqert(1^2 + 2^2)=Sqrt(5). Angle = arctan(2)

image.png.46209e715d90015ce18744ef0436c9d2.png

Now, there is a formula with arctan difference. It is: arctan α - arctan β = arctan [(α-β) / (1+αβ)], let's apply it here.image.png.c794c306585d0a9249632ecec897f3e7.png

Still does not evaluate into something nice. Oh well. The number is image.png.a694a7315b158b3ec04cf4d871db006c.png   

Now we need to convert it to a+bi form.

Polar notation m*e^(j*phi) converts into Cartesian notation (?) like this:
a=m*cos(phi)
b=m*sin(phi)
And we get to use a couple of formulas here:
sin-of-arctan.gif
cos-of-arctan.gif

Let's go:

image.png.fc460c775b9d644cbb4bccbf05993419.png

image.png.a2749370678cb1cfb1f5dc3088783894.png

So, 

image.png.022f0f293651a658ab16f6b88d874af6.png

Now we just need to add the remaining part:

0.8 - 0.6j +  (1+j) = 1.8 + 0.4j

4 hours ago, Mirage said:

b. e jπ/2 + j

This one's easier:

a=cos(pi/2)=0
b=sin(pi/2)=1
e^(j*pi/2)=j
j+j=2j
e jπ/2 + j = 2j

4 hours ago, Mirage said:

(4+j3)/(1-j)

Again, this can be j*3 or j^3. Let's say it's j^3 this time:

image.png.bd08b78ef45987d38822904e562084c6.png

Let's try to solve this a bit different, like a normal fraction. Multiply both parts by (1-j). We'll take advantage of the fact that j^2 = -1 and the fact that 1/j = -j.

image.png.7f636bc7186a2adc33147c0afef38b4a.png

4 hours ago, Mirage said:

e jπ + (1+j)/(1-j)

This seems easy, let's try:

image.png.819b1a160bcd7dcb73fd63f7a3a4f27e.pngimage.png.b2c6f3b9ea7845ca7d0849e31a30f49c.png

image.png.cf8720e269174b9e58c447ba8016f01b.png

image.png.3ad74ec6a52141d5ada1f42b4695ca6e.png (this is known as Euler's identity)

image.png.358c8c18af0c840c492e30f3c6905041.png

 

I think I got all of them correctly, but I may have made a mistake with signs or something, You should verify this.

Disregard everything after this line - I made some mistakes and pasted the fixed equations, but I cannot find them among the attachments (because the thumbnails show only a tiny portion) to delete them.

image.png

image.png

image.png

image.png

Edited by Pentium100
Hid the wrong equations
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@Pentium100 Thank you so much! That was much more help than I expected. I shall review and check my work against yours. I'm truly very grateful of your instruction. A true Twilight in our midst!

886353009_1842408__safe_artist-colon-hosikawa_princessluna_alicorn_animated_blackbackground_crown_eyeshadow_female_gif_hoofshoes_horn_jewelry_makeup_mare_open.gif.2c5c3c5e42b5be6312e90f0cf9c1d244.gif

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I’d totally help out with homework too if I wasn’t so bad with math >~> I study medicine though so it anybody needs help with subjects going in that direction I’d gladly provide it!

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