hehe. Didn't think it was possible, eh?
Here. Proof.
1 + 1 = 3
If we let x = y,
x-y+y = y
x-y+y ÷ x-y = y ÷ x-y
If we simplify this we get:
x-y ÷ x-y + y ÷ x-y = y ÷ x-y
OR
1+y ÷ x-y = y ÷ x-y
1 = y ÷ x-y - y ÷ x-y (This means 1 = 0)
Now knowing x = y or 1=1 is true and that 1=0 (or 0=1), we show:
0 = 1,
1 = 1
and
1 = 1.
If we add all these equations we get:
0+1+1 = 1+1+1
or, fully simplified
1+1=3
Is there somewhere I went wrong? It took a while to work all of this out, so some feedback on this would help.
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