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Anywho, we're at 2 now!

Why didn't you share your sandwich with Simon?! It would have gained us an extra 5 minutes!!

 

Indeed, I am the lord of numbers!. Thanks to your encouragement, I shall conjure up another question!

 

The current count is equal to the area between the function y=sin(2x+π) and the x axis from x=0 to x=3π/2.

 

Anyone who can answer the above question or either of my questions on the previous page will win a brohoof. The questions I've asked so far are:

 

1. Show that the shortest distance between the lines L1 and L2 is 2, where L1=<2,1,-3>+t<2,-1,2> and L2=<2,0,1>+s<4,2,0>

 

2. Show that the gradient of the function y=sin(x) at x=2π is 1.

 

3. Show that the area between the function y=sin(2x+π) and the x axis from x=0 to x=3π/2 is 3 units2.

 

 

*sucks at maths*

Hm.. 3?  ^_^


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I shall stop generating maths for now. Time to count normally. 4!!!!

 

The brohoof-worthy questions so far (Now arranged in order of what I think is easiest to hardest):

 

1. Show that the gradient of the function y=sin(x) at x=2? is 1.

 

2. Show that the infinite series 1/2+1/4+1/8+1/16+...+1/(2n)+... (i.e. post-27784-0-84894400-1410767135.jpg) is equal to 1.

 

3. Show that the area between the function y=sin(2x+?) and the x axis from x=0 to x=3?/2 is 3 units2.

 

4. Show that the shortest distance between the lines L1 and L2 is 2, where L1=<2,1,-3>+t<2,-1,2> and L2=<2,0,1>+s<4,2,0>

 

 

 

I may start offering hints later. I need to keep the maths going until Arylett reveals who 'Her' is!

 

Also, Crimson, I'm afraid I can't accept '3' as the answer. The questions do include the word 'show'.

Edited by FortyTwo42

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'Her'? Who's 'Her'? See, now I have to keep making more maths because I want to know who 'Her' is.

 

The current count is equal to the result of the infinite series 1/2+1/4+1/8+1/16...+1/(2n)+... (Or, using summation notation, the result of attachicon.gifSummation Question.jpg)

 

Don't do it! You don't know WHAT you're doing... aaaah.... STOP THIS MATH!  NOW, BEFORE IT'S TOO LATE!

 

The Crimson Cross... its power is radiating to stop all the counts!

 

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Aether Velvet is the name of the OC in my avatar. Drawn by me. 

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