Emerald Heart

Meson's answer is technically correct, and the computer will tell you it's right too, but it won't do you any good when it looks like the point of the question is to learn point-slope form.

Use y2 - y1 = m(x2 - x1) to find the slope. Then plug the slope and one point into y - y1 = m(x - x1). Solve for y like usual.

(I hope that made sense)

Looks like they beat me to it.

I think @Meson Bolt had a typo but he got the right answer. Here is how I do it. The equation for a straight line is y =mx+b where m is the slope. The slope is "rise over run" which means how much it chages vertically (y direction) divided by the change horizontally (x dirextion). This helps you remember the formula

m = (y2 - y1) / (x2-x1) = (y1-y2)/(x1-x2)

It doesn't matter if you do the first point minus second, or second minus first, it is the same answer. m = (-2.9 - (-4.4)) / (-3.2 - (-4.2))  = 1.5

Once you have m, pick a point and put it into the y=mx+b

-2.9 = (1.5)(-3.2) + b

b = -2.9 - (1.5)(-3.2) = 1.9

Remember subtracting a negative is the same as adding.

y = 1.5 x + 1.9