mega thread Last Poster Wins

[FortyTwo42 1,287]

Nah. That's not going to happen.

 

Behold my creation, and tremble in fear! 

The Flummoxer.png

If you have any questions, ask them before you start. And don't let my bad handwriting confuse you! 

 

Subscript means it's in a different base! 10110₂ is binary, for example.

 

At -5^-10, the -10 is an negative exponent, not just a regular old negative ten!

For the first term, does the square root only apply to the -42 in the numerator or the whole fraction? Likewise for the exponent in the second term.

What does the 2 above the square root in the last term indicate? If it's indicating to take the second root of the term, that's just the square root and the 2 isn't needed.

[Gatekeeper Giggle 2,902]

For the first term, does the square root only apply to the -42 in the numerator or the whole fraction? Likewise for the exponent in the second term.

What does the 2 above the square root in the last term indicate? If it's indicating to take the second root of the term, that's just the square root and the 2 isn't needed.

It only applies to the -42 in the numerator! 

 

Sorry, my mistake/bad writing. I intended that one to be one of those fancy cube roots.

[Mars Orbit 729]

*waits patiently for this thread to die so i can be the true last poster*

[Gatekeeper Giggle 2,902]

*waits patiently for this thread to die so i can be the true last poster*

Oh, hey Mars!   Long time no see!

[Mars Orbit 729]

Oh, hey Mars!   Long time no see!

Stormgiggle?! How have ya been?

[Gatekeeper Giggle 2,902]

Stormgiggle?! How have ya been?

I'm great!    I've just been waiting for the apocalypse. Once all you pesky humans/ponies perish in the unending horrors of oblivion, I'll have the last post!   

 

Also, did you see that math problem I made? There is no way 42 will be able to solve it! 

[Mars Orbit 729]

I'm great! I've just been waiting for the apocalypse. Once all you pesky humans/ponies perish in the unending horrors of oblivion, I'll have the last post!

 

Also, did you see that math problem I made? There is no way 42 will be able to solve it!

The internet would be down in the event of an apocalypse. Your plan is flawed!!!

 

 

...is the answer 7?

Edited December 21, 2015 by Mars Orbit

[Gatekeeper Giggle 2,902]

The internt would be down in the apocalypse. Your plan is flawed!!!

 

 

...is the answer 7?

As long as the servers that hold MLPForums survive, I can always just travel to Canada and put in my post manually.

 

I highly doubt it... but maybe?  

[Mars Orbit 729]

As long as the servers that hold MLPForums survive, I can always just travel to Canada and put in my post manually.

 

I highly doubt it... but maybe?

 

So if i just went to canada, put the post in manually, destroy the servers, then destroy canada i could get the last post?

 

...is the answer 17?

[Gatekeeper Giggle 2,902]

So if i just went to canada, put the post in manually, destroy the servers, then destroy canada i could get the last post?

 

...is the answer 17?

Yep. You'll never be able to pull it off though. 

 

Absolutely not!

[Mars Orbit 729]

Yep. You'll never be able to pull it off though. 

 

Absolutely not!

You say that like you could.

 

....how about....-3?

[Gatekeeper Giggle 2,902]

You say that like you could.

 

....how about....-3?

Well, I certainly wouldn't destroy Canada or anything else.

 

What!? There are no negative numbers in my equation!

[Mars Orbit 729]

Well, I certainly wouldn't destroy Canada or anything else.

 

What!? There are no negative numbers in my equation!

It would be entirely worth it.

 

OR ARE THERE?!?! *X-files theme plays*

[Gatekeeper Giggle 2,902]

It would be entirely worth it.

 

OR ARE THERE?!?! *X-files theme plays*

I'm fairly positive the Canadians would disagree with you.

 

Ahh... I love that theme.

 

Also, I think my math question killed 42.

[Mars Orbit 729]

I'm fairly positive the Canadians would disagree with you.

 

Ahh... I love that theme.

 

Also, I think my math question killed 42.

They might, but it's the apocalypse, so i don't think it would make much of a difference

 

Math: Killing people since the beginning of math

[Gatekeeper Giggle 2,902]

They might, but it's the apocalypse, so i don't think it would make much of a difference

 

Math: Killing people since the beginning of math

Hmm... you have no idea what form the apocalypse will take. There may be survivors.

 

Ha. I kid. Either he's still working on it or he left to do other things. 

[Mars Orbit 729]

Hmm... you have no idea what form the apocalypse will take. There may be survivors.

 

Ha. I kid. Either he's still working on it or he left to do other things.

 

Neither do you, there may be no survivors.

 

Nope. He died.

[FortyTwo42 1,287]

It only applies to the -42 in the numerator! 

 

Sorry, my mistake/bad writing. I intended that one to be one of those fancy cube roots.

The Flummoxer.png

Alright, let's handle this term by term.

 

√(-42)/(-10) = -(√42)i/10 (approximately -0.6481i)

 

(π/251)^( (√(-42)) / ((-5)^(-10)) ) = (π/251)^( ((-5)^10)*(√42)i ) = (π/251)^(-9765625i√42)

The exponent is imaginary, so use the property a^(bi)=cos(b*ln(a))+i*sin(b*ln(a))

(π/251)^(-9765625i√42) = cos(-9765625*(√42)*(π/251))+i*sin(-9765625*(√42)*(π/251)) = cos(9765625*(√42)*(π/251))-i*sin(9765625*(√42)*(π/251))  (approximately -0.9593+0.2823i)

 

(√25)^(-3)=1/((√25)^3)=1/(5^3)=1/125 (or 0.008)

 

1=1

 

³√(-10)=-(10)^(1/3) (approx. -2.1544)

 

10110₂/√(-101₃) = (2⁴*1+2³*0+2²*1+2¹*1+2⁰*0)/√(-(3²*1+3¹*0+3⁰*1)) = (16+4+2)/√(-(9+1)) = 22/√(-10) = 22/(i*√10) = -22*i/√10 = (-22*i*√10)/(√10)² = (-11*i*√10)/5 (approx. -6.9570i)

 

³√(FA67₁₆) = ³√(16³*15+16²*10+16¹*6+16⁰*7) = ³√(4096*15+256*10+16*6+7) = ³√(61440+2560+96+7) = ³√(61440+2560+96+7) = ³√64103 (approx. 40.0214)

 

 

 

So, we have:

(  (-(√42)i/10)  +(  (cos(9765625*(√42)*(π/251))-i*sin(9765625*(√42)*(π/251))  *  (1/125)  )+  (1)  )/((  (-(10)^(1/3))  *  (³√64103)  )/  ((-11*i*√10)/5)  )

(I bolded and spaced out the operations between terms that came from the equation itself to make it easier to read)

 

 

That’s probably the best answer you’re going to get in exact form. If you want an approximate numerical answer, just put in the approximations I made for each part:

 

(  (-0.6481i)  +(  (-0.9593+0.2823i)  *  (0.008)  )+  (1)  )/((  (-2.1544)  *  (40.0214)  )/  (-6.9570i)  )

= (  (-0.6481i)  +  (-0.00767+0.00226i)  +  (1)  )/(  (-86.2221)  /  (-6.9570i)  )

= (  (0.99233-0.64584i  )/(  (-12.3936i)  )

= 0.0521+0.0801i

[Mars Orbit 729]

Alright, let's handle this term by term.

 

√(-42)/(-10) = -(√42)i/10 (approximately -0.6481i)

 

(π/251)^( (√(-42)) / ((-5)^(-10)) ) = (π/251)^( ((-5)^10)*(√42)i ) = (π/251)^(-9765625i√42)

The exponent is imaginary, so use the property a^(bi)=cos(b*ln(a))+i*sin(b*ln(a))

(π/251)^(-9765625i√42) = cos(-9765625*(√42)*(π/251))+i*sin(-9765625*(√42)*(π/251)) = cos(9765625*(√42)*(π/251))-i*sin(9765625*(√42)*(π/251))  (approximately -0.9593+0.2823i)

 

(√25)^(-3)=1/((√25)^3)=1/(5^3)=1/125 (or 0.008)

 

1=1

 

³√(-10)=-(10)^(1/3) (approx. -2.1544)

 

10110₂/√(-101₃) = (2⁴*1+2³*0+2²*1+2¹*1+2⁰*0)/√(-(3²*1+3¹*0+3⁰*1)) = (16+4+2)/√(-(9+1)) = 22/√(-10) = 22/(i*√10) = -22*i/√10 = (-22*i*√10)/(√10)² = (-11*i*√10)/5 (approx. -6.9570i)

 

³√(FA67₁₆) = ³√(16³*15+16²*10+16¹*6+16⁰*7) = ³√(4096*15+256*10+16*6+7) = ³√(61440+2560+96+7) = ³√(61440+2560+96+7) = ³√64103 (approx. 40.0214)

 

 

 

So, we have:

(  (-(√42)i/10)  +(  (cos(9765625*(√42)*(π/251))-i*sin(9765625*(√42)*(π/251))  *  (1/125)  )+  (1)  )/((  (-(10)^(1/3))  *  (³√64103)  )/  ((-11*i*√10)/5)  )

(I bolded and spaced out the operations between terms that came from the equation itself to make it easier to read)

 

 

That’s probably the best answer you’re going to get in exact form. If you want an approximate numerical answer, just put in the approximations I made for each part:

 

(  (-0.6481i)  +(  (-0.9593+0.2823i)  *  (0.008)  )+  (1)  )/((  (-2.1544)  *  (40.0214)  )/  (-6.9570i)  )

= (  (-0.6481i)  +  (-0.00767+0.00226i)  +  (1)  )/(  (-86.2221)  /  (-6.9570i)  )

= (  (0.99233-0.64584i  )/(  (-12.3936i)  )

= 0.0521+0.0801i

 

Shhhhhhhh.

You're supposed to be dead

[FortyTwo42 1,287]

Shhhhhhhh.

You're supposed to be dead

I'm so glad you all have so much confidence in me.

[Gatekeeper Giggle 2,902]

Alright, let's handle this term by term.

 

√(-42)/(-10) = -(√42)i/10 (approximately -0.6481i)

 

(π/251)^( (√(-42)) / ((-5)^(-10)) ) = (π/251)^( ((-5)^10)*(√42)i ) = (π/251)^(-9765625i√42)

The exponent is imaginary, so use the property a^(bi)=cos(b*ln(a))+i*sin(b*ln(a))

(π/251)^(-9765625i√42) = cos(-9765625*(√42)*(π/251))+i*sin(-9765625*(√42)*(π/251)) = cos(9765625*(√42)*(π/251))-i*sin(9765625*(√42)*(π/251))  (approximately -0.9593+0.2823i)

 

(√25)^(-3)=1/((√25)^3)=1/(5^3)=1/125 (or 0.008)

 

1=1

 

³√(-10)=-(10)^(1/3) (approx. -2.1544)

 

10110₂/√(-101₃) = (2⁴*1+2³*0+2²*1+2¹*1+2⁰*0)/√(-(3²*1+3¹*0+3⁰*1)) = (16+4+2)/√(-(9+1)) = 22/√(-10) = 22/(i*√10) = -22*i/√10 = (-22*i*√10)/(√10)² = (-11*i*√10)/5 (approx. -6.9570i)

 

³√(FA67₁₆) = ³√(16³*15+16²*10+16¹*6+16⁰*7) = ³√(4096*15+256*10+16*6+7) = ³√(61440+2560+96+7) = ³√(61440+2560+96+7) = ³√64103 (approx. 40.0214)

 

 

 

So, we have:

(  (-(√42)i/10)  +(  (cos(9765625*(√42)*(π/251))-i*sin(9765625*(√42)*(π/251))  *  (1/125)  )+  (1)  )/((  (-(10)^(1/3))  *  (³√64103)  )/  ((-11*i*√10)/5)  )

(I bolded and spaced out the operations between terms that came from the equation itself to make it easier to read)

 

 

That’s probably the best answer you’re going to get in exact form. If you want an approximate numerical answer, just put in the approximations I made for each part:

 

(  (-0.6481i)  +(  (-0.9593+0.2823i)  *  (0.008)  )+  (1)  )/((  (-2.1544)  *  (40.0214)  )/  (-6.9570i)  )

= (  (-0.6481i)  +  (-0.00767+0.00226i)  +  (1)  )/(  (-86.2221)  /  (-6.9570i)  )

= (  (0.99233-0.64584i  )/(  (-12.3936i)  )

= 0.0521+0.0801i

Wow. That's really impressive 42!  You may want to get a professional to double check you, I have no idea how to cheak that.

 

Open only if you want more math to solve:

 

 

 

Oh yes. Very well done 42. You've managed to solve a small part of a much larger math problem. FOOL! Did you really think me so easily defeated!? Gaze upon the true form of the Flummoxer and despair!

 

 

 

Shhhhhhhh.

You're supposed to be dead

 

Neither do you, there may be no survivors.

 

Nope. He died.

Maybe. Are you willing to take that chance?

 

It's funny that right after you said that he came back.

 

I'm so glad you all have so much confidence in me.

I never doubted you for a second!  I did, however, doubt you for a few minutes. 

[CinnamonPop 3,350]

I'm so glad you all have so much confidence in me.

Wow! It would probably take me a week to figure that out. I'd need a week to study that.

 

I'm only in second year American high school combined algebra and geometry. We are on the topic of "Mother Functions"

Edited December 21, 2015 by CinnamonPop

[Gatekeeper Giggle 2,902]

Wow! It would probably take me a week to figure that out. I'd need a week to study that.

 

I'm only in second year American high school combined algebra and geometry. We are on the topic of "Mother Functions"

So... just what is a mother function?

[Mr Dash 1,820]

Math is boring. But you know what isn't? Winning!!

[Gatekeeper Giggle 2,902]

Math is boring. But you know what isn't? Winning!!

How could you say such a thing!?