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Mars Orbit

Mars Orbit 729

I'm fairly positive the Canadians would disagree with you.

 

Ahh... I love that theme.

 

Also, I think my math question killed 42.

They might, but it's the apocalypse, so i don't think it would make much of a difference

 

Math: Killing people since the beginning of math

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Gatekeeper Giggle

Gatekeeper Giggle 2,902

They might, but it's the apocalypse, so i don't think it would make much of a difference

 

Math: Killing people since the beginning of math

Hmm... you have no idea what form the apocalypse will take. There may be survivors.

 

Ha. I kid. Either he's still working on it or he left to do other things. 

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Mars Orbit

Mars Orbit 729

Hmm... you have no idea what form the apocalypse will take. There may be survivors.

 

Ha. I kid. Either he's still working on it or he left to do other things.

 

Neither do you, there may be no survivors.

 

Nope. He died.

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FortyTwo42

FortyTwo42 1,287

It only applies to the -42 in the numerator! 

 

Sorry, my mistake/bad writing. I intended that one to be one of those fancy cube roots.

attachicon.gifThe Flummoxer.png

Alright, let's handle this term by term.

 

√(-42)/(-10) = -(√42)i/10 (approximately -0.6481i)

 

(π/251)^( (√(-42)) / ((-5)^(-10)) ) = (π/251)^( ((-5)^10)*(√42)i ) = (π/251)^(-9765625i√42)

The exponent is imaginary, so use the property a^(bi)=cos(b*ln(a))+i*sin(b*ln(a))

(π/251)^(-9765625i√42) = cos(-9765625*(√42)*(π/251))+i*sin(-9765625*(√42)*(π/251)) = cos(9765625*(√42)*(π/251))-i*sin(9765625*(√42)*(π/251))  (approximately -0.9593+0.2823i)

 

(√25)^(-3)=1/((√25)^3)=1/(5^3)=1/125 (or 0.008)

 

1=1

 

3√(-10)=-(10)^(1/3) (approx. -2.1544)

 

101102/√(-1013) = (24*1+23*0+22*1+21*1+20*0)/√(-(32*1+31*0+30*1)) = (16+4+2)/√(-(9+1)) = 22/√(-10) = 22/(i*√10) = -22*i/√10 = (-22*i*√10)/(√10)2 = (-11*i*√10)/5 (approx. -6.9570i)

 

3√(FA6716) = 3√(163*15+162*10+161*6+160*7) = 3√(4096*15+256*10+16*6+7) = 3√(61440+2560+96+7) = 3√(61440+2560+96+7) = 3√64103 (approx. 40.0214)

 

 

 

So, we have:

(  (-(√42)i/10)  +(  (cos(9765625*(√42)*(π/251))-i*sin(9765625*(√42)*(π/251))  *  (1/125)  )+  (1)  )/((  (-(10)^(1/3))  *  (3√64103)  )/  ((-11*i*√10)/5)  )

(I bolded and spaced out the operations between terms that came from the equation itself to make it easier to read)

 

 

That’s probably the best answer you’re going to get in exact form. If you want an approximate numerical answer, just put in the approximations I made for each part:

 

(  (-0.6481i)  +(  (-0.9593+0.2823i)  *  (0.008)  )+  (1)  )/((  (-2.1544)  *  (40.0214)  )/  (-6.9570i)  )

= (  (-0.6481i)  +  (-0.00767+0.00226i)  +  (1)  )/(  (-86.2221)  /  (-6.9570i)  )

= (  (0.99233-0.64584i  )/(  (-12.3936i)  )

= 0.0521+0.0801i

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Mars Orbit

Mars Orbit 729

Alright, let's handle this term by term.

 

√(-42)/(-10) = -(√42)i/10 (approximately -0.6481i)

 

(π/251)^( (√(-42)) / ((-5)^(-10)) ) = (π/251)^( ((-5)^10)*(√42)i ) = (π/251)^(-9765625i√42)

The exponent is imaginary, so use the property a^(bi)=cos(b*ln(a))+i*sin(b*ln(a))

(π/251)^(-9765625i√42) = cos(-9765625*(√42)*(π/251))+i*sin(-9765625*(√42)*(π/251)) = cos(9765625*(√42)*(π/251))-i*sin(9765625*(√42)*(π/251))  (approximately -0.9593+0.2823i)

 

(√25)^(-3)=1/((√25)^3)=1/(5^3)=1/125 (or 0.008)

 

1=1

 

3√(-10)=-(10)^(1/3) (approx. -2.1544)

 

101102/√(-1013) = (24*1+23*0+22*1+21*1+20*0)/√(-(32*1+31*0+30*1)) = (16+4+2)/√(-(9+1)) = 22/√(-10) = 22/(i*√10) = -22*i/√10 = (-22*i*√10)/(√10)2 = (-11*i*√10)/5 (approx. -6.9570i)

 

3√(FA6716) = 3√(163*15+162*10+161*6+160*7) = 3√(4096*15+256*10+16*6+7) = 3√(61440+2560+96+7) = 3√(61440+2560+96+7) = 3√64103 (approx. 40.0214)

 

 

 

So, we have:

(  (-(√42)i/10)  +(  (cos(9765625*(√42)*(π/251))-i*sin(9765625*(√42)*(π/251))  *  (1/125)  )+  (1)  )/((  (-(10)^(1/3))  *  (3√64103)  )/  ((-11*i*√10)/5)  )

(I bolded and spaced out the operations between terms that came from the equation itself to make it easier to read)

 

 

That’s probably the best answer you’re going to get in exact form. If you want an approximate numerical answer, just put in the approximations I made for each part:

 

(  (-0.6481i)  +(  (-0.9593+0.2823i)  *  (0.008)  )+  (1)  )/((  (-2.1544)  *  (40.0214)  )/  (-6.9570i)  )

= (  (-0.6481i)  +  (-0.00767+0.00226i)  +  (1)  )/(  (-86.2221)  /  (-6.9570i)  )

= (  (0.99233-0.64584i  )/(  (-12.3936i)  )

= 0.0521+0.0801i

 

Shhhhhhhh.

You're supposed to be dead

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Gatekeeper Giggle

Gatekeeper Giggle 2,902

Alright, let's handle this term by term.

 

√(-42)/(-10) = -(√42)i/10 (approximately -0.6481i)

 

(π/251)^( (√(-42)) / ((-5)^(-10)) ) = (π/251)^( ((-5)^10)*(√42)i ) = (π/251)^(-9765625i√42)

The exponent is imaginary, so use the property a^(bi)=cos(b*ln(a))+i*sin(b*ln(a))

(π/251)^(-9765625i√42) = cos(-9765625*(√42)*(π/251))+i*sin(-9765625*(√42)*(π/251)) = cos(9765625*(√42)*(π/251))-i*sin(9765625*(√42)*(π/251))  (approximately -0.9593+0.2823i)

 

(√25)^(-3)=1/((√25)^3)=1/(5^3)=1/125 (or 0.008)

 

1=1

 

3√(-10)=-(10)^(1/3) (approx. -2.1544)

 

101102/√(-1013) = (24*1+23*0+22*1+21*1+20*0)/√(-(32*1+31*0+30*1)) = (16+4+2)/√(-(9+1)) = 22/√(-10) = 22/(i*√10) = -22*i/√10 = (-22*i*√10)/(√10)2 = (-11*i*√10)/5 (approx. -6.9570i)

 

3√(FA6716) = 3√(163*15+162*10+161*6+160*7) = 3√(4096*15+256*10+16*6+7) = 3√(61440+2560+96+7) = 3√(61440+2560+96+7) = 3√64103 (approx. 40.0214)

 

 

 

So, we have:

(  (-(√42)i/10)  +(  (cos(9765625*(√42)*(π/251))-i*sin(9765625*(√42)*(π/251))  *  (1/125)  )+  (1)  )/((  (-(10)^(1/3))  *  (3√64103)  )/  ((-11*i*√10)/5)  )

(I bolded and spaced out the operations between terms that came from the equation itself to make it easier to read)

 

 

That’s probably the best answer you’re going to get in exact form. If you want an approximate numerical answer, just put in the approximations I made for each part:

 

(  (-0.6481i)  +(  (-0.9593+0.2823i)  *  (0.008)  )+  (1)  )/((  (-2.1544)  *  (40.0214)  )/  (-6.9570i)  )

= (  (-0.6481i)  +  (-0.00767+0.00226i)  +  (1)  )/(  (-86.2221)  /  (-6.9570i)  )

= (  (0.99233-0.64584i  )/(  (-12.3936i)  )

= 0.0521+0.0801i

Wow. That's really impressive 42! :squee: You may want to get a professional to double check you, I have no idea how to cheak that.

 

Open only if you want more math to solve:

 

 

jon-stewart.gif

 

Oh yes. Very well done 42. You've managed to solve a small part of a much larger math problem. FOOL! Did you really think me so easily defeated!? Gaze upon the true form of the Flummoxer and despair!

 

post-29563-0-88043600-1450682418_thumb.png

 

 

Shhhhhhhh.

You're supposed to be dead

:wacko:

 

Neither do you, there may be no survivors.

 

Nope. He died.

Maybe. Are you willing to take that chance?

 

It's funny that right after you said that he came back.

 

I'm so glad you all have so much confidence in me. >_>

I never doubted you for a second!  :D I did, however, doubt you for a few minutes.  :adorkable:

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CinnamonPop

CinnamonPop 3,341

(edited)

I'm so glad you all have so much confidence in me. >_>

Wow! It would probably take me a week to figure that out. I'd need a week to study that. :catface:

 

I'm only in second year American high school combined algebra and geometry. We are on the topic of "Mother Functions" :yay:

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Mr Dash

Mr Dash 1,818

 

 

Nope, scientists like math. That answer is illogical and incorrect.

 

Implying that to be a scientist, one has to like math.......

 

I like science. I don't like math. But most science involves some sort of math. Doesn't mean the scientist likes math.

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Gatekeeper Giggle

Gatekeeper Giggle 2,902

Implying that to be a scientist, one has to like math.......

 

I like science. I don't like math. But most science involves some sort of math. Doesn't mean the scientist likes math.

Your logic is dangerously unsound. I'm not hearing any sound from it. None at all. 

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